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| Author: | ag [ Tue Oct 09, 2007 12:17 pm ] |
| Post subject: | area and circumference of circle, triangle square |
Came across this question. The length of the circumference of a circle equals the perimeter of a triangle of equal sides and also the perimeter of a square. The areas covered by the circle, triangle and square are c, t and s respectively. What can be said about the relation between c, t and s 1. s > t > c 2. c > t > s 3. c > s > t 4. s > c > t is there a way to solve it without actually taking a value for the circumference? |
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| Author: | 2iim [ Wed Oct 10, 2007 11:04 am ] |
| Post subject: | It is a standard Mathematical axiom |
You can verify the answer using numerical examples. However, please note that what is given is a mathematical axiom For a given circumference or perimeter, an equilateral triangle will be the regular polygon with the smallest area and a circle will the figure with the largest area. A square with 4 sides having the same perimeter as that of an equilateral triangle will have an area larger than the equilateral triangle. Similarly, a regular pentagon's area will be larger than that of a square for the same perimeter and so on and so forth. The answer to the question is option (3). i.e., C > S > T |
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